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This is a popular problem for FasterXML's Jackon JSON developers. I faced it when I had with similiar POJOs:

package net.package.dogs.retrievers

@JsonTypeInfo(use = JsonTypeInfo.Id.CLASS, include = JsonTypeInfo.As.PROPERTY, property = "family")
@JsonSubTypes(value = {
    @JsonSubTypes.Type(value = LabradorRetriever.class),
    @JsonSubTypes.Type(value = GoldenRetriever.class)
})
public abstract class Retriever {
    private String name;
    private Color color;

    public Retriever() {}

    public Retriever(String name, Color color) {
        this.name = name;
        this.color = color;
    }

    public String bark() {
        return "You can't hear me but I'm barking"; 
    }
}
package net.package.dogs.retrievers

public class LabradorRetriever extends Retriever {
    public LabradorRetriever() {
        super();
    }

    public LabradorRetriever(String name, Color color) {
        super(name, color);
    }

    public String bark() {
        return "Ruff! Ruff!";
    }

    public String fetchDucks() {
        return "ufff...";
    }
}
package net.package.dogs.retrievers

public class GoldenRetriever extends Retriever {

    public GoldenRetriever() {
        super();
    }

    public GoldenRetriever(String name, Color color) {
        super(name, color);
    }

    public String bark() {
        return "Wruuff! Wruff!";
    }
}
public enum Color {
    YELLOW,
    CHOCOLATE,
    BLACK
}

This classes match the following JSON messages...

{
    "family" : "net.package.dogs.retrievers.GoldenRetriever",
    "name" : "Goldie",
    "color" : "YELLOW"
}
{
    "family" : "net.package.dogs.retrievers.LabradorRetriever",
    "name" : "Cookie",
    "color" : "CHOCOLATE"
}

But instead I want to have a different different "race" as follows.

{
    "family" : "GOLDEN_RETRIEVER",
    "name" : "Goldie",
    "color" : "YELLOW"
}
{
    "family" : "LABRADOR_RETRIEVER",
    "name" : "Cookie",
    "color" : "CHOCOLATE"
}

How should I fill JsonTypeInfo and JsonSubTypes to match this previous JSON message?

mkobit
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Hugo Tavares
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1 Answers1

1

Here is one way you could accomplish this:

  1. Change the @JsonTypeInfo to use JsonTypeInfo.Id.NAME:

    @JsonTypeInfo(use = JsonTypeInfo.Id.NAME, ...
    
  2. Add @JsonTypeName for name resolution:

    @JsonTypeName("LABRADOR_RETRIEVER")
    public class LabradorRetriever extends Retriever {
    
mkobit
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