How to find period of the clock pulse with frequency.

Question

for example: the period is 10ms and i need to find the frequency it would look like this: f= 1/t = 1/10ms = 100Hz because (10ms=.01 seconds, so its really 1/.01=100)

I understand that but when it changes to a larger unit such as GHz i get confused.

Example: if the frequency of a clock pulse is 2GHz, what is the period of the clock pulse?

My thoughts: F= 2GHz= 2 000 000 000Hz
T= 1/F = 1/2 000 000 000?? i somehow doubt this is even close to the answer. Could someone explain this one to me? Thanks a million.

i know that period and frequency are reciprocals so T=1/F and F=1/T — stacker, Apr 14 '15 at 18:11

bitspill · Accepted Answer · 2015-04-14T18:47:09.433

0

The period is correct as you calculated it.

P = 1/F
P = 1/2GHz = 1/(2×10^9)
P = 0.0000000005s (second)
P = 0.0000005ms (millisecond)
P = 0.0005us (microsecond)
P = 0.5ns (nanosecond)
P = 500ps (picosecond)

Another way to look at it is 2Ghz is 2×10^7 times faster than 100hz so the period should be 2×10^7 times shorter

2Ghz/100Hz = 2×10^7
10ms/(2×10^7) = 500ps

edited Apr 14 '15 at 18:47

answered Apr 14 '15 at 18:15

bitspill

131
7

Could my answer also be T=1/F = 1/2Ghz= 0.5us? – stacker Apr 14 '15 at 18:40
It should be 0.5ns or 0.0005us – bitspill Apr 14 '15 at 18:41
Just expanded the breakdown of second to picosecond in the answer – bitspill Apr 14 '15 at 18:47
1

thanks for all the help Bitspill, i completely understand it now! Really appreciate it. – stacker Apr 14 '15 at 18:51
No problem. Now continue on and make something awesome! – bitspill Apr 14 '15 at 18:53

How to find period of the clock pulse with frequency.

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