How do I insert format str and don't remove the matched regular expression in input string in boost::regex_replace() in C++?

Question

I want to put space between punctuations and other words in a sentence. But boost::regex_replace() replaces the punctuation with space, and I want to keep a punctuation in the sentence! for example in this code the output should be "Hello . hi , "

regex e1("[.,]");
std::basic_string<char> str = "Hello.hi,";
std::basic_string<char> fmt = " ";
cout<<regex_replace(str, e1, fmt)<<endl;

Can you help me?

score 1 · Accepted Answer · answered Jun 02 '10 at 07:32

1

You need to use a replacement variable in your fmt string. If I understand the documentation correctly, then in the absence of a flags field, you'll want to use a Boost-Extended format string.

In that sub-language, you use $& to mean whatever was matched, so you should try defining fmt as:

std::basic_string<char> fmt = " $& ";

That should change each punctuation into that same character, surrounded by spaces.

answered Jun 02 '10 at 07:32

swestrup

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and he can replace his std::basic_string by just std::string – Nikko Jun 02 '10 at 07:39
Yes, I'd noticed that, but decided to concentrate on answering the question that was asked. – swestrup Jun 03 '10 at 09:37

How do I insert format str and don't remove the matched regular expression in input string in boost::regex_replace() in C++?

1 Answers1