2 C Errors Incompatible type and expected type

Question

I'm trying to store 3 sets of 5 double numbers from user input. I need to store the information in a 3 x 5 array and compute the average of each set of five values.

I can't figure out how to fix two errors.

First error: hw9.c:27:2 error: incompatible type for argument 1 of 'set_average' set_average (array[ROW][COL]); ^

Second error: hw9.c:8:6: note: expected 'double (*)[5]' but argument is of type 'double' void set_average(double array[ROW][COL]);

Thanks for any help and suggestions.

#include <stdio.h>
#define ROW 3
#define COL 5
void set_average(double array[ROW][COL]);
void all_average(double array[ROW][COL]);
void find_largest(double array[ROW][COL]);
int main(void)
{
    double array[ROW][COL];
    int i, j;

    printf("Enter three sets of five double numbers.\n");
    for (i = 0; i < 3; i++)
        for (j = 0; j < 5; j++)
        {
            printf("Enter elements until done.\n");
            printf("Enter %d%d: ",i+1,j+1);
            scanf("%le", &array[i][j]);
        }   
    printf("Done entering numbers.\n");
    printf("Now it's time to compute the average of each set of five values\n");

    set_average (array[ROW][COL]);

    return 0;
}

void set_average(double array[ROW][COL])
{
    int r;      //row
    int c;
    double sum;
    double avg; //average
        for (r = 0; r < ROW; r++)
            for (c = 0; c < COL; c++)
            {
                sum += array[r][c];
            }
    avg = sum / 5;
    printf("The average is %le\n", avg);
}

Anto Jurković · Answer 1 · 2015-04-10T05:27:17.453

0

You are calling function as

set_average (array[ROW][COL]);

instead of

set_average (array);

Function is defined as void set_average(double array[ROW][COL]) so it expects an array of ROW. Each has an array of COL items which are doubles. Error was reported because function was called with just one double as argument.

edited Apr 10 '15 at 05:27

answered Apr 10 '15 at 05:21

Anto Jurković

11,188
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Himanshu · Answer 2 · 2015-04-10T05:33:37.330

0

you need to pass full array to the function

set_average (array);

As you are passing

set_average (array[ROW][COL]);

it will send only single value i.e array[3][5]

In set_average function you have not initialize value of double sum; . Initialize sum with zero, otherwise you will get wrong Output.

edited Apr 10 '15 at 05:33

answered Apr 10 '15 at 05:22

Himanshu

4,327
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score 0 · Answer 3 · answered Apr 10 '15 at 05:51

try this:
------------------
#include <stdio.h>
#define ROW 3
#define COL 5

void set_average(double array[][COL]);

int main(void)
{
        double array[ROW][COL];
        int i, j;

        printf("Enter three sets of five double numbers.\n");
        for (i = 0; i < 3; i++)
                for (j = 0; j < 5; j++)
                {
                        printf("Enter elements until done.\n");
                        printf("Enter %d%d: ",i+1,j+1);
                        scanf("%le", &array[i][j]);
                }
        printf("Done entering numbers.\n");
        printf("Now it's time to compute the average of each set of five values\n");

        set_average( array );

        return 0;
}

void set_average( double array[ ][5] )
{
        int r;      //row
        int c;
        double sum;
        double avg; //average
        for (r = 0; r < ROW; r++)
                for (c = 0; c < COL; c++)
                {
                        sum += array[r][c];
                }
        avg = sum / 5;
        printf("The average is %le\n", avg);
}

2 C Errors Incompatible type and expected type

3 Answers3