Add argc for Windows cmd

Question

Using Linux, when running a C++ program that takes a .txt file as an argc. i.e.

int main(int argc, char *argv[])

I can simply compile it, then type ./a.out file.txt

When using windows, after compiling it, how do i then run it including the file.txt as the argc?

`a.exe file.txt` should do the trick, assuming you're running the program from the command line (since it is a command-line program, after all). Or you could drag and drop `file.txt` onto `a.exe`. — Harry Johnston, Apr 10 '15 at 03:35
@ImraazRally: the question very clearly asks for `file.txt` to be an argument, *not* redirected to standard input. — Harry Johnston, Apr 10 '15 at 03:53

score 2 · Accepted Answer · answered Apr 10 '15 at 03:35

2

You do it this same way, only the name of the executable changes e.g., program_name.exe file.txt.

answered Apr 10 '15 at 03:35

James Adkison

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score 1 · Answer 2 · answered Apr 10 '15 at 03:39

In Linux you would normally use ./a.out file.txt (the default in Linux is that the current directory is not searched for executables). In Windows' standard command interpreter you can just write a file.txt, assuming that you have named your program a.exe (Windows' command interpreter searches the current directory regardless of your PATH). Different compilers differ in how you name the executable file, but with g++ use -o a and with Visual C++ use /Fea.

One way to run the Windows command interpreter is Windows key+R, then type cmd in the Run-dialog that pops up.

score 0 · Answer 3 · answered Apr 10 '15 at 03:36

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Run "cmd"
Change directory to the executable file exists with command "cd"
Exactly do that you did in Linux.

answered Apr 10 '15 at 03:36

Mr. Handy

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Add argc for Windows cmd

3 Answers3