I'm having this error: error c2064: term does not evaluate to a function taking 0 arguments. The thing is the function takes 0 arguments and I call 0 arguments, and I don't understand what's wrong.
RWLock* rwl = new RWLock();
std::thread t1(&RWLock::read);
That's the call to the function. And this is the function:
void read();
Does somebody know what the problem is? Thanks in advance!
All non-static member functions have a hidden argument, that becomes the this pointer in the member function If you want to use a non-static member function as a thread, you have to provide this hidden argument when starting the thread:
std::thread t1(&RWLock::read, rwl);
I am pretty sure, that read() is not a static function. That is, you declared it as:
void read()
instead of:
static void read()
Non-static member function takes always one additional argument - implicit this pointer. Make read() static and it should work.
If read() cannot be static, pass an additional argument to std::thread - a pointer to object, that read() will work on. In this case it should be rwl:
RWLock* rwl = new RWLock();
std::thread t1(&RWLock::read, rwl);
