Regex for HTML RESPONSE BODY present under div tag

Question

I need to build a regex for extracting the value present under value field. i.e "f70a8c3d0a6cbe2e235c7fd1dd27d052df7412ea"

HTML RESPONSE BODY : Note: I have pasted just a minor part of the response....but formToken key is unique

<div class="hidden">
    <input name="formToken    type="hidden"
            value="f70a8c3d0a6cbe2e235c7fd1dd27d052df7412ea"    
    />
</div>

I wrote the below regex but it returned nothing:

regex("formToken" type="hidden" value="([^"]*)"/>).find(0).exists, found nothing

Did you try `regex("""value="([^"]*)"""")`? I mean, you might need to use triple quotation marks. — Wiktor Stribiżew, Apr 07 '15 at 23:08
Thanks for replying Stribizhev...but the above reponse was just a part of HTML Body It also has more than 50 Values...example ................ — Sunnx, Apr 07 '15 at 23:10
[Dont parse (X)html with a regex](http://stackoverflow.com/questions/1732348/regex-match-open-tags-except-xhtml-self-contained-tags/1732454#1732454). — Willem Van Onsem, Apr 07 '15 at 23:10

score 0 · Answer 1 · answered Apr 08 '15 at 05:05

0

Can you try this?

regex("type="hidden".*value="(.*?)[ \t]*"/>).find(0).exists

answered Apr 08 '15 at 05:05

pogo

Thanks Pogo, but as I said earlier we were having more than 1 match for the above regex and our only unique key is formToken, so I think we need to build on that line. – Sunnx Apr 08 '15 at 21:27
It would be easier if you give me your full input and expected output. – pogo Apr 09 '15 at 01:18

score 0 · Answer 2 · answered Apr 08 '15 at 16:33

0

Instead of a regex, you could use a css selector check which is probably way easier once you have ids or css classes to search for.

answered Apr 08 '15 at 16:33

Stephane Landelle

Thanks Stephane .check(css("input[name='formToken']", "value").saveAs("formTokex")) – Sunnx Apr 09 '15 at 01:50

score 0 · Answer 3 · answered Apr 09 '15 at 01:50

0

Thank you all....I was able to get formToken using css

.check(css("input[name='formToken']", "value").saveAs("formTokex"))

answered Apr 09 '15 at 01:50

Sunnx

score 0 · Answer 4 · answered Sep 14 '18 at 11:37

0

Works like this for me:

.exec(http("request_1")
        .get("<<<<YOUR_URL>>>>>")
        .check(css("form[name='signInForm']", "action").saveAs("urlPath"))

and later printing it:

println(session( "urlPath" ).as[String])

answered Sep 14 '18 at 11:37

Adrian Madaras

4 Answers4