I tried the same code by replacing default values in the code below, I got '-1'. But the actual output is '1'. How???
int i = (byte) + (char) - (int) + (long) - 1;
System.out.println(i);
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eddie
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JavaJitendra
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What values did you replace default values with? – Moishe Lipsker Apr 03 '15 at 10:46
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int i = (int) (0+0-0+0L-1); @MoisheLipsker – JavaJitendra Apr 03 '15 at 10:49
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1You misinterpreted this. `(long)` is not 0. All the operators here are unary. – RealSkeptic Apr 03 '15 at 10:50
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And just a side note: `0` is an `int`, not a `byte` or `char`, so you changed the types as well. – T.J. Crowder Apr 03 '15 at 10:51
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This is a duplicate. The challenge is finding the other. – Dawood ibn Kareem Apr 03 '15 at 10:54
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1@DavidWallace Challenge accepted. :-) – RealSkeptic Apr 03 '15 at 10:55
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Shucks, I had http://stackoverflow.com/q/9651760 – Dawood ibn Kareem Apr 03 '15 at 10:56
1 Answers
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i will be evaluated as (+(-(+(-1))), which will be evaluated as (-(-1)), which is 1.
Konstantin Yovkov
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