I would like to call 'contains' on my Iterables :-)
2 Answers
The reason Iterable
does not have a contains
method is because the way it is defined can have direct consequences on variance. Basically, there are two type signatures that make sense for it:
def contains(v: Any): Boolean
def contains(v: A): Boolean
The second definition has increased type safety. However, A
, which is the type parameter of collection, appears in a contra-variant position, which forces the collection to be invariant. It could be defined like this:
def contains[B >: A](v: B): Boolean
but that wouldn't offer any improvement over the first signature, using Any
.
As a consequence of this, you'll see that immutable.Seq
is co-variant and uses the first signature, while immutable.Set
is invariant and uses the second signature.

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Note: `contains` **is** implemented using the signature `contains[A1 >: A](elem: A1)` in `SeqLike` (at least in Scala 2.11.8). I do not think this is the same as using `Any` - it places some constraints on the `B` type - you can pass `Any`, but you cannot pass a type which is known to be unrelated. – Suma Nov 25 '16 at 10:19
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@Suma Sure you can. Go ahead and try. If you pass an unrelated type, `A1` will be inferred to be the common supertype. And because everything is descendant from `Any`, then all types have a common supertype with each other. – Daniel C. Sobral Nov 30 '16 at 21:56
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You are right. Is there any reason why is the signature in the library as it is, and not with `Any`, as you write, then? – Suma Dec 01 '16 at 07:14
I don't know why contains
is not defined on Iterable
or TraversableOnce
, but you could easily define it yourself:
class TraversableWithContains[A](underlying: TraversableOnce[A]) {
def contains(v: Any): Boolean =
underlying.exists(_ == v)
}
implicit def addContains[A](i: Iterable[A]) = new TraversableWithContains(i)
and use it as if it were defined on Iterable:
val iterable: Iterable[Int] = 1 to 4
assert(iterable.contains(3))
assert(!iterable.contains(5))

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