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I am trying to perform a search on Deezer by sending the following intent:

Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://www.deezer.com/search/" + query));
this.startActivity(intent);

In a previous version the web browser opened with a link saying "Open in Deezer" (or the like). But in the current version this doesn't work anymore.

Is there any way to open the Deezer app and perform a search? I have already tried the following (without success):

Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("deezer://search/" + query));
this.startActivity(intent);
Yash Sampat
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Markus
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2 Answers2

5

There are many deeplinks you can use to search for content inside the Deezer app. You do have the basic search like this : 

Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("deezer://www.deezer.com/search/" + query));
this.startActivity(intent);

But you can also be more precise : 

// Search for an artist, will display the best match
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("deezer-query://www.deezer.com/artist?query" + query));
this.startActivity(intent);

// Search for an album, will display the best match
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("deezer-query://www.deezer.com/album?query" + query));
this.startActivity(intent);

// Search for a track, will display the best match
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("deezer-query://www.deezer.com/track?query" + query));
this.startActivity(intent);
XGouchet
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2

I believe it should be

Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("deezer://www.deezer.com/search/" + query));
this.startActivity(intent);

The scheme of the Uri needs to be deezer. You have set it as http.

Try this. This should work.

Yash Sampat
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