Don't stop parsing after first exception

Question

for default JavaCC stops parsing after first exception (TokenMgrError) but is a way to parse all input until EOF?

I need that to list all errors instead of stoping at the first one.

Thanks.

Any reason why you're not just catching the exception, storing that somewhere, and continuing about your parse operation? — Makoto, Mar 18 '15 at 17:35

score 1 · Answer 1 · answered Mar 19 '15 at 02:37

In general you should avoid TokenMgeErrors. Usually this can be accomplished with a "catch all" rule -- see the FAQ for details.

Now you are left with a ParseException. You can deal with these using try-catch. See the JavaCC documentation for information on that.

score 0 · Answer 2 · answered Mar 24 '15 at 18:54

You can use a method that skips all the tokens until the argument one:

void error_skipto(int kind){
    ParseException e = generateParseException();
    System.out.println(e.toString());
    Token t;
    do {
        t = getNextToken();
    } while (t.kind != kind);
}

and then call it in a non-terminal method:

void block(): {}
{
    try{
        < START > [code()] < END >

    }catch ( ParseException e ) {
        error_skipto(SEMICOLON);
        System.out.println( "Captured by: block()" );
    }
}

Don't stop parsing after first exception

2 Answers2