passing argument 2 of ‘strstr’ makes pointer from integer without a cast?

Question

what does this warning mean? I read some other posts about a similar question, but I'm still not understanding how to go about solving it.

# define EOT_CHAR '\04'
char buffer[MAXLINE];

            if ( strstr( buffer, EOT_CHAR ) != NULL )
            {
                break;
            }

score 5 · Answer 1 · answered Mar 15 '15 at 22:14

5

strstr is used to locate a substring and requires a pointer to a string as its second argument. To locate a character use strchr function.

answered Mar 15 '15 at 22:14

ouah

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Exactly. EOT_CHAR is a character, which is a special case of an integer in the C language. The strstr() function takes two pointers to characters, so the compiler was complaining that the second argument, which in you case was an integer, was being converted to a pointer. – Nick Stoughton Mar 18 '15 at 14:06

passing argument 2 of ‘strstr’ makes pointer from integer without a cast?

1 Answers1