This is where the collectingAndThen
collector is useful:
List<Integer> list = IntStream.range(0, 7).boxed()
.collect(collectingAndThen(toList(), ImmutableList::copyOf));
It applies the transformation to the List
you just built; resulting in an ImmutableList
.
Or you could directly collect into the Builder
and call build()
at the end:
List<Integer> list = IntStream.range(0, 7)
.collect(Builder<Integer>::new, Builder<Integer>::add, (builder1, builder2) -> builder1.addAll(builder2.build()))
.build();
If this option is a bit-verbose to you and you want to use it in many places, you can create your own collector:
class ImmutableListCollector<T> implements Collector<T, Builder<T>, ImmutableList<T>> {
@Override
public Supplier<Builder<T>> supplier() {
return Builder::new;
}
@Override
public BiConsumer<Builder<T>, T> accumulator() {
return (b, e) -> b.add(e);
}
@Override
public BinaryOperator<Builder<T>> combiner() {
return (b1, b2) -> b1.addAll(b2.build());
}
@Override
public Function<Builder<T>, ImmutableList<T>> finisher() {
return Builder::build;
}
@Override
public Set<Characteristics> characteristics() {
return ImmutableSet.of();
}
}
and then:
List<Integer> list = IntStream.range(0, 7)
.boxed()
.collect(new ImmutableListCollector<>());
Just in case the link disappears in the comments; my second approach could be defined in a static utility method that simply uses Collector.of
. It's simpler than creating your own Collector
class.
public static <T> Collector<T, Builder<T>, ImmutableList<T>> toImmutableList() {
return Collector.of(Builder<T>::new, Builder<T>::add, (l, r) -> l.addAll(r.build()), Builder<T>::build);
}
and the usage:
List<Integer> list = IntStream.range(0, 7)
.boxed()
.collect(toImmutableList());