want SAXParseException return -1

Question

When a SAXParseException occur I want the exception to return -1. but I dont know how I should do it because I can't handle that exceptions. Any ideas how I should do? At the moment when the exception occur it print this:

VARNING: org.xml.sax.SAXParseException: s4s-elt-character: Non-whitespace 
characters are not allowed in schema elements other than 'xs:appinfo' and 'xs:documentation'. Saw '1'.

Process finished with exit code 0

What is "it" and what do you mean "on a good why"? – Andy Turner Mar 12 '15 at 11:10 — Andy Turner, Mar 12 '15 at 11:10

score 0 · Accepted Answer · answered Mar 12 '15 at 11:13

0

Sounds like you need:

try {
  // whatever code might throw SAXParseException
} catch (SAXParseException e) {
  return -1;
}

answered Mar 12 '15 at 11:13

Andy Turner

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I've that but it still : Process finished with exit code 0 – Oliver Lagerbäck Westblom Mar 12 '15 at 11:16
Ah. This is what I meant by "what is "it"?": my answer assumed that this was in some method. The sledgehammer way is to change `return -1` to `System.exit(-1)`; however, I would not recommend doing that, but instead working out what is catching, logging and swallowing your exception. – Andy Turner Mar 12 '15 at 11:18
ye it worked with System.exit(-1). But why does it not return -1? – Oliver Lagerbäck Westblom Mar 12 '15 at 11:22
Please describe what "it" is. – Andy Turner Mar 12 '15 at 11:22
Omg sorry, if statement I have whas wrong! It was my fault not java.. – Oliver Lagerbäck Westblom Mar 12 '15 at 11:26
Thanks you Andy Turner for your help! – Oliver Lagerbäck Westblom Mar 12 '15 at 11:33

want SAXParseException return -1

1 Answers1