Please help me with this error in simple fizzbuzz program

Question

Syntax error near unexpected token 'if'

   for x in 1..100 
      if x % 3 == 0
        puts "Fizz"
      elsif (x % 5) == 0
        puts "Buzz"
      else
        puts x
      end
   end

weird, I'm running from Terminal and wrote with sublime text and it's not working. — goofiw, Mar 03 '15 at 01:43
Try putting brackets () around the if statement like this: if (x % 3 == 0) — Greg the Incredulous, Mar 03 '15 at 01:51
runs fine here as well. Are you running in IRB by any chance? — Jasdeep Singh, Mar 03 '15 at 01:55

score 1 · Answer 1 · answered Mar 04 '15 at 10:31

1

Thank you for the help. I was running the program incorrectly in the terminal. (. / vs 'ruby')

answered Mar 04 '15 at 10:31

goofiw

1 Answers1