PHP User gallery

Question

I already have an idea for how to create mysql database for a user gallery... But i have few questions:

Premise: i don't want to save photoes in a database for performance issue I already tried to save photoes in a database but then the site ( after a Lot of picture has been uploaded) becomes too slow

1. how can i load photoes with php?(FTP)
2. how can i create new directory on a server with php?

Thanks to all for your future answers Have a nice day Luca

Answer 1

You can use a basic file input in HTML and the php function move_uploaded_file , example:

html:

<form method="post" enctype="multipart/form-data">
    <input type="file" name="photo"/>
</form>

php:

    $file= $_FILES['photo'];
    if(move_uploaded_file($file['tmp_name'], "/path/to/a/directory")){
        echo "yeah";
    }

If the /directory does not exist, it will create it for you.

Answer 2

1. U can save the image's name in the database

here's a function i used to load jpeg images with a small size :

    function make_thumb($src, $dest, $desired_width) {

    /* read the source image */
    $source_image = imagecreatefromjpeg($src);
    $width = imagesx($source_image);
    $height = imagesy($source_image);
         /* find the "desired height" of this thumbnail, relative to the desired width */
    $desired_height = floor($height * ($desired_width / $width));

    /* create a new, "virtual" image */
    $virtual_image = imagecreatetruecolor($desired_width, $desired_height);

    /* copy source image at a resized size */
    imagecopyresampled($virtual_image, $source_image, 0, 0, 0, 0, $desired_width, $desired_height, $width, $height);

    /* create the physical thumbnail image to its destination with 100% quality*/
    imagejpeg($virtual_image, $dest,100);
}   



        $result=mysql_query("SELECT * FROM photos");

        while($row=mysql_fetch_array($result)){

        $photoname = $row['imgTitle'];

        $source = "../images/big/".$photoname;

        $destination = "../images/thumb/thumb_".$photoname ."";         

        $width = "200";

        make_thumb($source,$destination,$width);

}