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I got declaration of linked list:

typedef struct element *P_element;
typedef struct element {
         char *value;
         P_element next;
} ELEM;

P_element L = NULL;

and I have to create function add with this header:

void Add (P_element *START_LIST, *END_LIST; char *elm)

But after I create code only with this code

typedef struct element *P_element;
typedef struct element
{
    char *value;
    P_element next;
} ELEM;

P_element L = NULL;

void Add(P_element *START_LIST, *END_LIST; char elm)
{

}
int main(int argc, char *argv[]) {
    return 0;
}

I got error:

Parameter 'START_SEZ'has just a forward declaration

It's my first time with this error and I'm not sure, how to solve this problem. I'm even not sure, why is P_element *START_LIST, *END_LIST; in function header, but now I can't ask my teacher.

Deduplicator
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Sk1X1
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1 Answers1

1

i think its just a type in your declaration, no semikolon is allowd for separating paramters

try this

void Add(P_element *START_LIST, P_element *END_LIST, char elm)
{

}
Ulrich Beck
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