Bash variable format

Question

I have the following code:

#!/bin/sh
uname=`awk 'NR>1{print $1}' foo.txt`
echo $uname

If I execute the command awk 'NR>1{print $1}' foo.txt by itself, I get the following format:

abc123
Apple
Test

When I save the command as a variable and echo it, the output becomes:

abc123 Apple Test

How would I go about making sure the output of $uname will be in the first output form listed above?

Ed Morton · Accepted Answer · 2015-02-16T03:10:47.977

4

Simply quote your variable as you ALWAYS should unless you have a specific purpose in mind by leaving it unquoted and fully understand all of the implications:

echo "$uname"

Btw you should use

var=$(cmd)

instead of the deprecated

var=`cmd`

edited Feb 16 '15 at 03:10

answered Feb 16 '15 at 03:01

Ed Morton

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Easy enough! It's been a minute, shaking off rust and still learning! – swam Feb 16 '15 at 03:02
Just waiting for the time limit to let me click! – swam Feb 16 '15 at 03:13

Bash variable format

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