Java - How to break a long statement

Question

How do I break a long line of code like this into several lines in Java?

System.out.println("Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy tex")

Sorry, I mean in the editor. I'm using TextWrangler, and my program is wider than the screen. — Margo Eastham, Feb 15 '15 at 17:52
@JigarJoshi: are you seriously suggesting to download a full IDE just for format a line of String? You must be joking right? — Nazgul, Feb 15 '15 at 17:53
Not just for this purpose, IDEs are better to use than simple text editor — jmj, Feb 15 '15 at 17:54

score 3 · Answer 1 · edited Jun 21 '18 at 12:25

3

have you tried this?

System.out.println("Lorem Ipsum is simply dummy text"
                   + " of the printing and typesetting industry. "
                   + "Lorem Ipsum has been the industry's "
                   + "standard dummy tex");

edited Jun 21 '18 at 12:25

moffeltje

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answered Feb 15 '15 at 17:52

Nazgul

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score 1 · Accepted Answer · answered Feb 15 '15 at 17:52

You could do

System.out.println("Lorem Ipsum is simply dummy text of the printing" +  
                    "and typesetting industry. Lorem Ipsum has been " + 
                    "the industry's standard dummy tex");

The resultant String will be the same as the original at the bytecode level

score 1 · Answer 3 · answered Feb 15 '15 at 17:52

1

use String concatination, like

System.out.println("Lorem Ipsum is simply dummy text of the printing and typesetting industry." +
        " Lorem Ipsum has been the industry's standard dummy tex");

answered Feb 15 '15 at 17:52

jmj

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score 1 · Answer 4 · answered Feb 15 '15 at 17:52

Try something like:

System.out.println("Lorem Ipsum is simply dummy text of the printing and" + 
" typesetting industry. Lorem Ipsum has been the industry's" +
" standard dummy tex")

Use "+" to concatenate two string which lives in two different lines.

score 1 · Answer 5 · answered Feb 15 '15 at 17:53

You can also apply line breaks- and either do it with more than a single command, like Rei did - but with a print on each part and the final one will be println, or use the \n special character:

System.out.println("Lorem Ipsum is simply dummy text of the printing\n" +  
                "and typesetting industry. Lorem Ipsum has been\n " + 
                "the industry's standard dummy tex");

score 1 · Answer 6 · answered Feb 15 '15 at 18:03

1

Try this:System.out.println("Lorem Ipsum is simply dummy text of the "+ "printing and typesetting industry. Lorem Ipsum has been the industry's "+ "standard dummy tex");

answered Feb 15 '15 at 18:03

Dhruv Ramani

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RobertS · Answer 7 · 2015-02-15T18:40:13.027

If you have String as :

System.out.println("Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy tex");

Than you can do it this vay :

System.out.println("Lorem Ipsum is simply dummy text of the printing and typesetting industry."  
                  +"Lorem Ipsum has been the industry's standard dummy tex");

Or you can split your String: Add any character where you want to split String or use some char that is already in String.

String string1 = "Lorem Ipsum is simply dummy text of the printing and typesetting industry.-Lorem Ipsum has been the industry's standard dummy tex";

String[] parts = string1.split("-");
String part0 = parts[0]; // Lorem Ipsum is simply dummy text of the printing and typesetting industry.
String part1 = parts[1]; //Lorem Ipsum has been the industry's standard dummy tex
System.out.println(part0);

output: Lorem Ipsum is simply dummy text of the printing and typesetting industry.

Note : if you want to split by "." , it stands for every character so

instead of

split(".");

use

split("\\.");

or

split(Pattern.quote("."));

To test beforehand if the string contains a -, just use

String#contains()

if (string.contains("-")) {
    // Split it. 
} 
else {
  throw new IllegalArgumentException("String " + string1 + " does not contain-"); 
 }

Nice going there, fully explained detail solution that invites him to learn more. +1 — A. Abramov, Feb 16 '15 at 04:38

Java - How to break a long statement

7 Answers7