SendTo menu and single instance program

Question

I'm making a program through which I will be able to send files to an FTP server just by right clicking "SendTo". The problem is that every time I click "SendTo" it opens a new exe file and it works as a separate program. I need to make it somehow to send the file with the already open program.

Thank you.

score 2 · Accepted Answer · answered May 17 '10 at 19:02

2

Here is an example application with source code: Single Instance Application, Passing Command Line Arguments.

The examples uses .Net Remoting to pass the arguments between instances but you can change it to use WCF, sockets or pipes.

answered May 17 '10 at 19:02

Giorgi

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score 1 · Answer 2 · answered May 17 '10 at 19:22

You can achieve a single instance with a Mutex.

Place this in your startup class. E.g. Program.cs

private static Mutex _mutex;

[STAThread]
static void Main (string[] args)
{
      // Ensure only one instance runs at a time
      _mutex = new Mutex (true, "MyMutexName");
      if (!_mutex.WaitOne (0, false))
      {
            return;
      }
}

But check MSDN for details: http://msdn.microsoft.com/en-us/library/ms686927%28VS.85%29.aspx

SendTo menu and single instance program

2 Answers2