How to match regex in java

Question

I want a pattern like this: GJ-16-RS-1234 and I have applied following patterns but they are not working.

My regex patterns are:

String str_tempPattern = "(^[A-Z]{2})\\-([0-9]{2})\\-([A-Z]{1,2})\\-([0-9]{1,4}$)";

String str_tempPattern = "(^[A-Z]{2})-([0-9]{1,2})-([A-Z]{1,2})-([0-9]{1,4})$";

String str_tempPattern = "^[A-Z]{2}\\-[0-9]{1,2}\\-[A-Z]{1,2}\\-[0-9]{1,4}$";

And I am using text watcher to check for any change in the aftertextchange()

Pattern p = Pattern.compile(str_tempPattern, Pattern.CASE_INSENSITIVE | Pattern.DOTALL);
    Matcher m = p.matcher(s);

    if (m.find()){

    }

I am pasing this string and matching with those regex patterns mentioned above... — Ravi Yadav, Feb 14 '15 at 04:45
@user3138859 your regex works for me. Show us the full code. — Avinash Raj, Feb 14 '15 at 04:50
@AvinashRaj I have mentioned total three patterns... which one working for you... — Ravi Yadav, Feb 14 '15 at 04:51
Are you expecting it to return you back `GJ-16-RS-1234` after being matched? — hwnd, Feb 14 '15 at 04:51
all https://regex101.com/r/dR8wY2/1, https://regex101.com/r/dR8wY2/2 , https://regex101.com/r/dR8wY2/3 — Avinash Raj, Feb 14 '15 at 04:52
@hwnd i am just returning boolean . I am calling the method from afterTextChanged() of textwatcher — Ravi Yadav, Feb 14 '15 at 04:53
did you want the return type to be bool? Then use matches method. `string.matches("[A-Z]{2}\\-[0-9]{1,2}\\-[A-Z]{1,2}\\-[0-9]{1,4}");` — Avinash Raj, Feb 14 '15 at 04:56
@AvinashRaj How to use that link of regex101.com I have mentioned the regex expression and written test string ...but what to do after that — Ravi Yadav, Feb 14 '15 at 05:00

score 8 · Accepted Answer · answered Feb 14 '15 at 05:04

8

Just set the condition using matches method.

if (string.matches("[A-Z]{2}\\-[0-9]{1,2}\\-[A-Z]{1,2}\\-[0-9]{1,4}")) 
{
        // Yes it matches
}
else
{
       // No it won't
}

answered Feb 14 '15 at 05:04

Avinash Raj

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How to match regex in java

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