How would you use XSL to transform all elements and all attributes from PascalCase to camelCase?

Question

I would like to transform ALL/ANY elements and attributes (not just the explicit elements/attributes in my small sample below) in my XML file from PascalCase to camelCase.

Does anyone have an XSL transform that can do this?

This:

<?xml version="1.0" encoding="utf-8" ?>
<Config Version="2" Name="Test">
    <Process Name="Main">
        X
    </Process>
</Config>

Should become this:

<?xml version="1.0" encoding="utf-8" ?>
<config version="2" name="Test">
    <process name="Main">
        X
    </process>
</config>

score 1 · Accepted Answer · answered Feb 13 '15 at 21:52

Try this:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
  <xsl:output method="xml" indent="yes"/>

  <!-- everything not mentioned below (e.g. text, comments, processing instructions) -->
  <xsl:template match="node()">
    <xsl:value-of select="."/>
  </xsl:template>

  <!-- attributes -->
  <xsl:template match="@*">
    <xsl:attribute name="{concat(translate(substring(local-name(), 1, 1),'QWERTYUIOPASDFGHJKLZXCVBNM','qwertyuiopasdfghjklzxcvbnm'), substring(local-name(), 2))}">
      <xsl:value-of select="."/>
    </xsl:attribute>
  </xsl:template>

  <!-- elements -->
  <xsl:template match="*">
    <xsl:element name="{concat(translate(substring(local-name(), 1, 1),'QWERTYUIOPASDFGHJKLZXCVBNM','qwertyuiopasdfghjklzxcvbnm'), substring(local-name(), 2))}">
      <xsl:apply-templates select="@* | node()"/>
    </xsl:element>
  </xsl:template>


</xsl:stylesheet>

NB: if using XSLT 2 you could replace the translate function with the lower-case function.

How would you use XSL to transform all elements and all attributes from PascalCase to camelCase?

1 Answers1