I was wondering how I could finish up this program. It's to perform a linear search on a list "ll" (which length is 31) for the user inputted item it, returning the user inputted numbers and their locations if they're found.
Problem: I'm not sure how to call the functions in this specific scenario, I don't really need to use pointers or pass a value, so the lack of these actually makes it more confusing for me, as those are fairly common scenarios.
#include <iostream> //enables usage of cin and cout
#include <cstring>
using namespace std;
int search (int i, int it, int ll, int z);
int printit (int i, int it, int ll, int z);
int main ()
{
int i,it,z;
int ll[] = {2,3,4,5,6,2,3,44,5,3,5,3,4,7,8,99,6,5,7,56,5,66,44,34,23,11,32,54,664,432,111}; //array hardwired with numbers
//call to search
return 0;
}
int search (int i, int it, int ll, int z)
{
cout << "Enter the item you want to find: "; //user query
cin >> it; //"scan"
for(i=0;i<31;i++) //search
{
if(it==ll[i])
{
//call to printit
}
}
return 0;
}
int printit (int i, int it, int ll, int z)
{
cout << "Item is found at location " << i+1 << endl;
return 0;
}