why my not_EOL function in C cannot detect EOL

Question

bool not_EOL (char c) {

    return ((c != '\n') && (c != '\0'));
}

while (not_EOL(gradients[i])) {
            // Read a position factor pair
            int a=sscanf(gradients + i, "(%d %lf)", &column, &factor);
            printf("%d%c",a,gradients[i]);
            if (a!=2) {
                usage(usage_message);

2 (9 100) (29 0) 38 (9 100) (49 390.043) 39 (9 100) (49 390.043) 41 (9 100) (49 390.043)

This is my not_EOL function and the file I am using. It seems that it does not detect EOL. The printf() statement prints 2(2(0, then usage() is called.

Your function looks ok to me. Perhaps you can post an [MCVE](http://stackoverflow.com/help/mcve). — R Sahu, Feb 07 '15 at 05:24
@R Sahu I update my question with a snippet of how I test the code. — yjrye, Feb 07 '15 at 14:49

score -1 · Answer 1 · answered Feb 07 '15 at 05:17

-1

Simplify the logic.

boo is_EOL(char c)
{
   return ((c == '\n') || (c == '\0'));
}

bool not_EOL (char c)
{
   return (!is_EOL(c));
}

answered Feb 07 '15 at 05:17

R Sahu

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why my not_EOL function in C cannot detect EOL

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