Find lowest common multiple of many datetime.timedelta objects

Question

Given a list of n timedelta objects, with the lowest denomination of time being minutes,

from datetime import timedelta as td

[td(days=1, hours=4, minutes=0),
 td(days=0, hours=2 minutes=30),
 td(days=3, hours=0 minutes=30),
 ...]

how can I find the lowest common multiple?

Answer 1

You could convert it all to seconds and get the LCM. Use timedelta.total_seconds()

https://docs.python.org/2/library/datetime.html