use regular expression in grammerbuilder in c#

Question

i am using SpeechRecognizer in c# . I want to use regular expression in grammerbuilder,here is my code.This code is not working.I want to pass any sentence example RE must pass 'this is stackoverflow', or any sentence or sentences.

Regex reg = new Regex(@"[a-z\-A-Z]*");
public Form1(){
InitializeComponent();    
try{
SpeechRecognizer spec = new SpeechRecognizer();
Choices chose = new Choices();
chose.Add(reg.ToString());
GrammarBuilder gb = new GrammarBuilder();
gb.Append(chose);
Grammar gm = new Grammar(gb);
spec.LoadGrammar(gm);
spec.SpeechRecognized += new EventHandler<SpeechRecognizedEventArgs>    (sre_SpeechRecognized);
spec.SpeechRecognitionRejected += new EventHandler<SpeechRecognitionRejectedEventArgs>(sre_SpeechRejected);
}

`I want to pass every word.` What do you mean by a word? Please explain more clrearly about the requirements. — Avinash Raj, Feb 05 '15 at 06:40
I have edited my question above,i want to pass any sentence or sentences — Farman Ameer, Feb 05 '15 at 06:46
You need to use dictation rather than an SRGS grammar. See http://stackoverflow.com/questions/10988117/combine-free-form-dictation-and-semantic-in-a-srgs-grammar — Ian Mercer, Feb 05 '15 at 06:50

score 0 · Answer 1 · answered Feb 05 '15 at 06:54

0

To allow one or more words.

Regex reg = new Regex(@"^[a-z-A-Z]+(?:\s[a-z-A-Z]+)*$");

I assume that the words contain alphabets or or - hyphen.

OR

Regex reg = new Regex(@"^\S+(?:\s\S+)*$");

\S+ matches one or more non-space characters.

answered Feb 05 '15 at 06:54

Avinash Raj

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use regular expression in grammerbuilder in c#

1 Answers1