PHP preg_split("/[.,] \s /", $content) invalid argument passed

Question

I am trying to split a variable that holds an articles content.

I want to loop through it to find keywords but I want to break up the content into an array.

preg_split("/[.,] \s /", $content);

So what I am doing here is splitting the content based on a "." or "," or a white space.

I was reading two different articles here on stack overflow one speaking about the split that is used like explode().

The other was about how the above syntex would work but I added the \s so I am assuming that is where I am going wrong. I have tried the \s within the bracket and out but still can't get it to work.

`preg_split("/[.,] \s /", "testing 12, 3")` works for me, so I'm guessing it's your `$content` that's the issue — Populus, Feb 02 '15 at 18:27
If is a split for any of this options it should be `"/[ ,.]/"` (note the white space) only. Your expression is saying that it should have a dot or a comma and a space and any space/enter/tab and another space — Jorge Campos, Feb 02 '15 at 18:28
Thanks for reply, its still not detecting the whitespace. Its breaking it down based on the ., but is now ignoring the whitespace. — Shinerrs, Feb 02 '15 at 18:29
Jorge Campos Excellent! that did it! I was thinking at the time you cant just put white space as whitespace could mean something different so I read \s means whitespace. Anyways all working thank you! — Shinerrs, Feb 02 '15 at 18:30
Take care with the ´\s´ becaus it also means tabs and enter chars ! — Jorge Campos, Feb 02 '15 at 18:32
I will add it as an answer so your question maybe usefull to others. — Jorge Campos, Feb 02 '15 at 18:54

score 0 · Accepted Answer · answered Feb 02 '15 at 18:56

If is a split for any of this options that you have mentioned space or . or , the right pattern should be

preg_split("/[ .,]/", $content);
              |_ Note the whitespace here

Your expression is saying that it should have a . or , and a space and any \s (space/enter/tab) and another space

PHP preg_split("/[.,] \s /", $content) invalid argument passed

1 Answers1