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Reading about how to use shift sequences to print characters from other character sets I've arrived at the following code (of which I'm sure the escape sequence is incorrect, however I do not know why):

#include <stdio.h>

int main(int argc, char *argv[])
{
    printf("\x1B\x28\x49\x0E\xB3"); /* Should print: ｳ */
    return 0;
}

This however is not working for me as it outputs a "?" in the terminal rather than the character "ｳ". My font does indeed have support for the character. If someone could explain what I'm doing incorrectly and how I would go about correcting this(still using shift sequences), that would be greatly appreciated.

Thank you

sheeldotme
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  • Can you print `ｳ` any other way to your terminal? (`terminfo` may or may not tell you whether your terminal supports this -- I cannot find the precise keywords to look for.) – Jongware Feb 02 '15 at 11:00
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    yes I can, when I run cat main.c, (which has `ｳ` in the comment, it is visible as expected. – sheeldotme Feb 02 '15 at 11:36

2 Answers2

1

What happens if you do echo 'ｳ' >/tmp/x && od -x /tmp/x - do you see the same hex characters as you are using in the example above? I'm betting not, and I've based this answer on that bet.

Your cat works because ｳ is encoded in your source file as UTF-8.

You have your terminal set to UTF-8 (or more likely it's just defaulting to UTF-8) so UTF-8 works, but Shift-JIS does not.

abligh
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1

Your are using ISO-2022-JP-3. Hence you need to write your program as follows:

int main ()
{
    // switch to JIS X 0201-1976 Kana set (1 byte per character)
    printf ("\x1B(I");

    printf ("\x33"); /* ｳ */

    // mandatory switch back to ASCII before end of line
    printf ("\x1B(B");

    printf ("\n");

    return 0;
}

Note however that it is unlikely to be the character set expected by the terminal (on linux, this is most likely UTF-8). You can use iconv to perform the conversion:

$ ./main | iconv -f ISO-2022-JP-3

Alternatively you can use iconv(3) to perform the conversion inside your program.