I am trying to make Single Table Inheritance into the Hibernate, but I am getting an error and I'm not able to figure it out.
My inherited class
@Entity
@Table(name = "Vechicle")
@Inheritance(strategy = InheritanceType.SINGLE_TABLE)
@DiscriminatorColumn(name="DTYPE")
public class Vehicle_object implements Serializable {
/**
*
*/
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column
private int vehicleid;
@Column(name = "Vehiclename")
private String vehiclename;
public Vehicle_object() {
super();
// TODO Auto-generated constructor stub
}
public int getVehicleid() {
return vehicleid;
}
public void setVehicleid(int vehicleid) {
this.vehicleid = vehicleid;
}
public String getVehiclename() {
return vehiclename;
}
public void setVehiclename(String vehiclename) {
this.vehiclename = vehiclename;
}
}
Child class.
@Entity
public class TwoWheeler extends Vehicle_object {
private String handle;
public String getHandle() {
return handle;
}
public void setHandle(String handle) {
this.handle = handle;
}
public TwoWheeler() {
super();
// TODO Auto-generated constructor stub
}
}
Second child.
@Entity
public class FourWheeler extends Vehicle_object {
private String stearing;
public String getStearing() {
return stearing;
}
public void setStearing(String stearing) {
this.stearing = stearing;
}
public FourWheeler() {
super();
// TODO Auto-generated constructor stub
}
}
and main class method.
try {
Session session = HibernateUtil.getSessionFactory().openSession();
session.beginTransaction();
Vehicle_object object = new Vehicle_object();
//object.setVehicleid(0);
object.setVehiclename("Car");
TwoWheeler twoWheeler = new TwoWheeler();
twoWheeler.setVehiclename("Apache");
twoWheeler.setHandle("Apache handle");
FourWheeler fourWheeler = new FourWheeler();
fourWheeler.setStearing("Ford Car Stearing");
fourWheeler.setVehiclename("FIGO FORD");
session.save(object);
session.save(twoWheeler);
session.save(fourWheeler);
session.getTransaction().commit();
session.clear();
session.close();
} catch (Exception e) {
// TODO: handle exception
e.printStackTrace();
}
getting this exception.
Caused by: com.microsoft.sqlserver.jdbc.SQLServerException: Invalid column name 'DTYPE'.
at com.microsoft.sqlserver.jdbc.SQLServerException.makeFromDatabaseError(SQLServerException.java:196)
at com.microsoft.sqlserver.jdbc.SQLServerStatement.getNextResult(SQLServerStatement.java:1454)
at com.microsoft.sqlserver.jdbc.SQLServerPreparedStatement.doExecutePreparedStatement(SQLServerPreparedStatement.java:388)
at com.microsoft.sqlserver.jdbc.SQLServerPreparedStatement$PrepStmtExecCmd.doExecute(SQLServerPreparedStatement.java:338)
at com.microsoft.sqlserver.jdbc.TDSCommand.execute(IOBuffer.java:4026)
at com.microsoft.sqlserver.jdbc.SQLServerConnection.executeCommand(SQLServerConnection.java:1416)
at com.microsoft.sqlserver.jdbc.SQLServerStatement.executeCommand(SQLServerStatement.java:185)
at com.microsoft.sqlserver.jdbc.SQLServerStatement.executeStatement(SQLServerStatement.java:160)
at com.microsoft.sqlserver.jdbc.SQLServerPreparedStatement.executeUpdate(SQLServerPreparedStatement.java:306)
at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate(ResultSetReturnImpl.java:186)
... 23 more
I have searched a lot but I'm not able to find the solution.