Compute the mean for each subject for different conditions

Question

Although I know how to compute the mean in R, I can't seem to understand how to do it for different conditions. Other posts that I have read were not as complicated.

>      Target/dictractor    TrialType    Bin0    Bin1    Bin2    Bin3
1          Target              2C           3       0       2       0
1          Target              2C           2       0       3       0
1          Target              2E           0       1       1       2
1          Target              2E           0       0       0       0
1        Distractor            2C           0       3       0       1
1        Distractor            2C           0       0       0       0
1        Distractor            2E           0       0       1       0
1        Distractor            2E           0       0       0       3
2          Target              2C           1       1       0       1
2          Target              2C           2       0       0       2
2        Distractor            2E           0       0       0       0
2        Distractor            2E           0       0       0       0

Given the data set above I would like to get the mean of each bin (Bin0, Bin1, Bin2) for each subject for each TrialType for Target/dictractor separately. For example, for subject 1 I would like to compute the mean of each bin, for TrialType 2C, in a Target condition, then the mean for each bin for TrialType 2E in a Target condition, then mean for each bin for TrialType 2C in Distractor condition and TrialType 2E in Distractor.

For the good description of your very first question with a sample data +1. :) — jazzurro, Feb 02 '15 at 00:31
`aggregate(. ~ Target.dictractor + TrialType + Subject, data=dat, FUN=mean)` would do it for an `aggregate` solution. — thelatemail, Feb 02 '15 at 01:43

jazzurro · Answer 1 · 2015-02-02T01:38:48.623

Here is my attempt. You can use group_by() and get the combinations of id, target and trial. For each combination, you want to get mean for bin0-bin3. This is something you can do with summarise_each() in this case.

mydf <- data.frame(id = c(1,1,1,1,1,1,1,1,2,2,2,2),
                   target = c("target", "target", "target", "target", "distractor",
                        "distractor", "distractor", "distractor",
                        "target", "target", "distractor", "distractor"),
                   trial = c("2c", "2c", "2e", "2e", "2c", "2c", "2e", "2e",
                             "2c", "2c", "2e", "2e"),
                   bin0 = c(3,2,0,0,0,0,0,0,1,2,0,0),
                   bin1 = c(0,0,1,0,3,0,0,0,1,0,0,0),
                   bin2 = c(2,3,1,0,0,0,1,0,0,0,0,0),
                   bin3 = c(0,0,2,0,1,0,0,3,1,2,0,0),
                   stringsAsFactors = FALSE)

library(dplyr)          
group_by(mydf, id, target, trial) %>%
summarise_each(funs(mean(., na.rm = TRUE)), bin0:bin3)

#  id     target trial bin0 bin1 bin2 bin3
#1  1 distractor    2c  0.0  1.5  0.0  0.5
#2  1 distractor    2e  0.0  0.0  0.5  1.5
#3  1     target    2c  2.5  0.0  2.5  0.0
#4  1     target    2e  0.0  0.5  0.5  1.0
#5  2 distractor    2e  0.0  0.0  0.0  0.0
#6  2     target    2c  1.5  0.5  0.0  1.5

Alternatively, you can try the data.table package to do the same operation.

foo <- setDT(mydf)[, lapply(.SD, mean), by = list(id, target, trial)]
print(foo)

#   id     target trial bin0 bin1 bin2 bin3
#1:  1     target    2c  2.5  0.0  2.5  0.0
#2:  1     target    2e  0.0  0.5  0.5  1.0
#3:  1 distractor    2c  0.0  1.5  0.0  0.5
#4:  1 distractor    2e  0.0  0.0  0.5  1.5
#5:  2     target    2c  1.5  0.5  0.0  1.5
#6:  2 distractor    2e  0.0  0.0  0.0  0.0

LyzandeR · Answer 2 · 2015-02-02T00:32:49.587

One way with the dplyr package is:

Data

df <- read.table(header=T,text='    Subject Target/dictractor    TrialType    Bin0    Bin1    Bin2    Bin3
1          Target              2C           3       0       2       0
1          Target              2C           2       0       3       0
1          Target              2E           0       1       1       2
1          Target              2E           0       0       0       0
1        Distractor            2C           0       3       0       1
1        Distractor            2C           0       0       0       0
1        Distractor            2E           0       0       1       0
1        Distractor            2E           0       0       0       3
2          Target              2C           1       1       0       1
2          Target              2C           2       0       0       2
2        Distractor            2E           0       0       0       0
2        Distractor            2E           0       0       0       0', stringsAsFactors=F)

Solution

df %>%
  group_by(Subject, Target.dictractor,TrialType) %>%
  summarise(mean_Bin0=mean(Bin0),
            mean_Bin1=mean(Bin1),
            mean_Bin2=mean(Bin2),
            mean_Bin3=mean(Bin3))

Output

Source: local data frame [6 x 7]
Groups: Subject, Target.dictractor

  Subject Target.dictractor TrialType mean_Bin0 mean_Bin1 mean_Bin2 mean_Bin3
1       1        Distractor        2C       0.0       1.5       0.0       0.5
2       1        Distractor        2E       0.0       0.0       0.5       1.5
3       1            Target        2C       2.5       0.0       2.5       0.0
4       1            Target        2E       0.0       0.5       0.5       1.0
5       2        Distractor        2E       0.0       0.0       0.0       0.0
6       2            Target        2C       1.5       0.5       0.0       1.5

Compute the mean for each subject for different conditions

2 Answers2