How to limit decimal places when using complex numbers

Question

sqrtnum_ = 0
sqrtnum_ = cmath.sqrt(snum_)

print "Using cmath.sqrt:"
print "    sqrt(", snum_, ") =      ", '%.12f' %sqrtnum_

How can I limit the number of decimal places. Normally I would use the above but it does not work with complex numbers

Can't You just do `"%.12f + %.12f j "%(sqrtnum_.real,sqrtnum_.imag)` — Bhargav Rao, Jan 31 '15 at 19:22

score 1 · Answer 1 · edited May 23 '17 at 12:12

1

This looks to be a duplicate of Formatting Complex Numbers

hopefully that helps!

(would have followed duplicate marking/commenting/etc protocol, but lack the rep for it)

edited May 23 '17 at 12:12

Community

answered Jan 31 '15 at 19:27

rbauer

score 1 · Accepted Answer · answered Jan 31 '15 at 19:28

1

You can use imag and real attributes of a complex number to get their respective values.

>>> a = cmath.sqrt(-1000)
>>> "%.12f + %.12fj"%(a.real,a.imag)
'0.000000000000 + 31.622776601684j'

This works for completely real numbers also

>>> a = cmath.sqrt(1000)
>>> "%.12f + %.12fj"%(a.real,a.imag)
'31.622776601684 + 0.000000000000j'

answered Jan 31 '15 at 19:28

Bhargav Rao

Can you specify a varible in the decimals? `"%(variable)f + %.12fj"%(a.real,a.imag)` – Mario Galván Feb 02 '15 at 03:38
@MarioGalván Yep, that is possible. For e.g: you need it `x` decimal places for real and `y` for the other, then you can do `("%%.%df + %%.%dfj"%(x,y))%(a.real,a.imag)` – Bhargav Rao Feb 02 '15 at 08:30
Thanks for the response, I have also tried using this: `"%.*f + %.12fj"%(a.real,a.imag)` and it works too. – Mario Galván Feb 02 '15 at 15:05
@MarioGalván You are welcome, There are surely numerous ways of doing this. – Bhargav Rao Feb 02 '15 at 18:39

2 Answers2