You can build the command with awk
and then pipe it to bash
:
grep --color -Ern --include=*.{php,html,phtml} --exclude-dir=vendor "todo|TODO|FIXME" . |\
awk -F: '{printf "svn blame \"%s\" | cat -n | grep \"%s\"\n", $1, $2}'
That prints one command per input line with the following format:
svn blame "${file}" | cat -n | grep "${linenumber}"
The varibales are replaces. When you execute the command as above they are only printed to the shell, that you can comfirm if everything is right. If yes add a last pipe to the in of the command that the ouput is redirected to bash
. The complete command would look like this:
grep --color -Ern --include=*.{php,html,phtml} --exclude-dir=vendor "todo|TODO|FIXME" . |\
awk -F: '{printf "svn blame \"%s\" | cat -n | grep \"%s\"\n", $1, $2}' | bash
A small notice: I think you want to print the line number extracterd in the first command, aren't you? But grep ${linenumber}
just gives the line containing the string ${linenumber}
. To print only the linenumber use that command: sed -n "2p"
to print line number 2 for example. The complete command would then look like this:
grep --color -Ern --include=*.{php,html,phtml} --exclude-dir=vendor "todo|TODO|FIXME" . |\
awk -F: '{printf "svn blame \"%s\" | cat -n | sed -n \"%sp\"\n", $1, $2}' | bash