how to check if a property value exists in array of objects in swift

Question

I am trying to check if a specific item (value of a property) exists in a array of objects, but could not find out any solution. Please let me know, what i am missing here.

        class Name {
            var id : Int
            var name : String
            init(id:Int, name:String){
                self.id = id
                self.name = name
            }
        }

        var objarray = [Name]()
        objarray.append(Name(id: 1, name: "Nuibb"))
        objarray.append(Name(id: 2, name: "Smith"))
        objarray.append(Name(id: 3, name: "Pollock"))
        objarray.append(Name(id: 4, name: "James"))
        objarray.append(Name(id: 5, name: "Farni"))
        objarray.append(Name(id: 6, name: "Kuni"))

        if contains(objarray["id"], 1) {
            println("1 exists in the array")
        }else{
            println("1 does not exists in the array")
        }

score 86 · Accepted Answer · answered Jan 29 '15 at 09:34

You can filter the array like this:

let results = objarray.filter { $0.id == 1 }

that will return an array of elements matching the condition specified in the closure - in the above case, it will return an array containing all elements having the id property equal to 1.

Since you need a boolean result, just do a check like:

let exists = results.isEmpty == false

exists will be true if the filtered array has at least one element

score 26 · Answer 2 · answered Apr 18 '17 at 10:57

26

In Swift 3:

if objarray.contains(where: { name in name.id == 1 }) {
    print("1 exists in the array")
} else {
    print("1 does not exists in the array")
}

answered Apr 18 '17 at 10:57

TheEye

9,280
2
42
58

How to return an object on the successful comparison? – Hemang Jun 07 '17 at 11:58
@Hemang use `filter` instead of `contains` if you need more than just testing condition. – Cœur Jun 30 '17 at 01:51
How to check one more condition under where: clause ? – IKKA Dec 18 '18 at 08:10

score 11 · Answer 3 · answered Feb 04 '16 at 15:43

11

In Swift 2.x:

if objarray.contains({ name in name.id == 1 }) {
    print("1 exists in the array")
} else {
    print("1 does not exists in the array")
}

answered Feb 04 '16 at 15:43

j_gonfer

1,547
21
21

score 11 · Answer 4 · answered Mar 11 '19 at 19:16

11

//Swift 4.2

    if objarray.contains(where: { $0.id == 1 }) {
        // print("1 exists in the array")
    } else {
        // print("1 does not exists in the array")
    }

answered Mar 11 '19 at 19:16

Danielvgftv

547
7
6

score 5 · Answer 5 · answered Jul 08 '20 at 21:30

There are mainly 2 viable options here.

Use the contains(where: method on objarray. I'm just making a minor modification to @TheEye's answer here:

if objarray.contains(where: { $0.id == 1 }) {
    print("1 exists in the array")
} else {
    print("1 does not exists in the array")
}

Override the Equatable protocol conformance requirement and just use contains, like this:

// first conform `Name` to `Equatable`
extension Name: Equatable {
    static func == (lhs: Name, rhs: Name) -> Bool {
        lhs.id == rhs.id
    }
}
// then
let firstName = Name(id: 1, name: "Different Name")
if objarray.contains(firstName) {
    print("1 exists in the array") // prints this out although the names are different, because of the override
} else {
    print("1 does not exists in the array")
}

score 4 · Answer 6 · answered Sep 15 '17 at 03:04

4

A small iteration on @Antonio's solution using the , (where) notation:

if let results = objarray.filter({ $0.id == 1 }), results.count > 0 {
   print("1 exists in the array")
} else {
   print("1 does not exists in the array")
}

answered Sep 15 '17 at 03:04

Stoff81

597
4
15

score 2 · Answer 7 · answered Sep 18 '21 at 23:30

struct Name {
    var id = Int()
    var name = String()
}

var objarray = [Name]()
objarray.append(Name(id: 1, name: "Nuibb"))
objarray.append(Name(id: 2, name: "Smith"))
objarray.append(Name(id: 3, name: "Pollock"))
objarray.append(Name(id: 4, name: "James"))
objarray.append(Name(id: 5, name: "Farni"))
objarray.append(Name(id: 6, name: "Kuni"))

var oneExists = !objarray.filter{ $0.id == 1 }.isEmpty

score 1 · Answer 8 · answered Jun 04 '15 at 06:18

1

This works fine with me:

if(contains(objarray){ x in x.id == 1})
{
     println("1 exists in the array")
}

answered Jun 04 '15 at 06:18

whitney13625

583
1
9
28

score 0 · Answer 9 · edited Nov 06 '18 at 23:10

0

signature:

let booleanValue = 'propertie' in yourArray;

example:

let yourArray= ['1', '2', '3'];

let contains = '2' in yourArray; => true
let contains = '4' in yourArray; => false

edited Nov 06 '18 at 23:10

Neil Lunn

148,042
36
346
317

answered Nov 06 '18 at 09:14

ricardoaleixoo

29
3

I believe the question states "array of **objects**" and not an "array of **string**" as you are providing an example for. So this does not actually address the question asked. – Neil Lunn Nov 06 '18 at 23:12

score -1 · Answer 10 · answered Dec 03 '17 at 23:16

-1

I went with this solution to similar problem. Using contains returns a Boolean value.

var myVar = "James"

if myArray.contains(myVar) {
            print("present")
        }
        else {
            print("no present")
        }

answered Dec 03 '17 at 23:16

Dan Korkelia

104
6

how to check if a property value exists in array of objects in swift

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