XSLT Type Checking

Question

Is it possible to check an elements ComplexType?

i have this (simplified):

complexType Record
complexType Customer extension of Record
complexType Person extension of Record 

<xsl:template match="/">
    <records>
    <xsl:apply-templates /> 
    </records>
</xsl:template>

<xsl:template match="!!! TYPECHECK FOR RECORD !!!" name="Record">
   <record><xsl:value-of select="." /></record>
</xsl:template>

is it possible to check elementstype incl. inheritence?

i dont know the elements name only that they are a subtype of Record.

schema 1:
   complexType name="Customer"
      extension base="Record"

   element name="customers"
      element name="customer" type="Customer"

schema 2:
   complexType name="Person"
      extension base="Record"

   element name="persons"
      element name="person" type="Person"

schema ?:
   complexType name="UnknownType"
      extension base="Record"

   element name="unknowns"
      element name="unknown" type="UnknownType"

xml 1:
<customers>
   <customer />
   <customer />
</customers>

xml 2:
<persons>
   <person />
   <person />
</persons>

xml ?:
<?s>
   <? />
   <? />
</?s>

the xml input ist custom so i have to match by the type (i think)

Good Question (+1). See my answer for a solution. :) – Dimitre Novatchev May 12 '10 at 13:28 — Dimitre Novatchev, May 12 '10 at 13:28

score 1 · Answer 1 · answered May 12 '10 at 13:28

1

In XPath 2.0 (and this means XSLT 2.0) one can use the instance-of operator:

. instance-of element(*, my:Record)

answered May 12 '10 at 13:28

Dimitre Novatchev

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score 0 · Answer 2 · edited May 23 '17 at 12:18

0

I'm not sure what you mean.

Different types have different tag names, and in xslt you should look at those to decide what type a node is.

Making sure a node indeed has a structure prescribed by your logic is not an xslt task. You should validate the document against a schema before passing it to an xslt processor to achieve this.

EDIT

I'm still not sure, but it seems like this question of mine could be of some help.

edited May 23 '17 at 12:18

Community

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answered May 12 '10 at 10:05

GSerg

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the element name is not bound to the type, its just a representation in a tree: complexType name="Record" ... element name="x" type="Record", element name="y" type="Record". both are Records. in my situation i cannot use the element name because i dont know it. – mo. May 12 '10 at 10:12
You may need to post your actual XML before we understand what you're asking. I'm lost, frankly. – Matt Gibson May 12 '10 at 10:22
Still not sure, but visit the link to see if it helps at all. – GSerg May 12 '10 at 13:16

XSLT Type Checking

2 Answers2