I am working on a site to share names of songs, and I have made a recommendation form that I include in every page. This recommendation form is in HTML and leads to a PHP action page, where the information received is added to a SQL table. Here is the code:
<?php
ob_start();
$host="localhost"; // Host name
$username="root"; // Mysql username
$password="MYPASSWORD"; // Mysql password
$db_name="DB NAME"; // Database name
$tbl_name="songshare"; // Table name
// Connect to server and select databse.
$link = mysqli_connect("$host", "$username", "$password")or die("cannot connect");
mysqli_select_db($link, "$db_name")or die("cannot select DB");
// Define $myusername and $mypassword
$song=$_POST['song'];
$album=$_POST['album'];
$artist=$_POST['artist'];
$linkitunes=$_POST['linkitunes'];
$artwork=$_POST['albumPic'];
// To protect MySQL injection (more detail about MySQL injection)
$song = stripslashes($song);
$album = stripslashes($album);
$artist = stripslashes($artist);
$song = mysqli_real_escape_string($link, $song);
$album = mysqli_real_escape_string($link, $album);
$artist = mysqli_real_escape_string($link, $artist);
$sql="SELECT * FROM $tbl_name WHERE song='$song'";
$result=mysqli_query($link, $sql);
if ($result->num_rows){
echo "Song already taken" . "<br />";
echo "<a href='/music.php'>music</a>";
exit();
}
$sql="INSERT INTO recommendation (user_id, artist, song, album, artwork, linkitunes)";
$sql = $sql . " VALUES ('$_SESSION['user_id']', '$artist', '$song', '$album'. '$artwork'. '$linkitunes');";
$result=mysqli_query($link, $sql);
if(!$result) {
echo "Recommendation failed" . "<br />";
echo $sql;
} else {
print "$song, $artist, $album";
}
ob_end_flush();
?>
I have checked that every username, password, link is correct and valid. My server does, in fact, run PHP. It doesn't seem to me like the PHP code is even running though.
Thank you so much in advance.
-Cameron