Javascript replace in a string

Question

I am familiar with the "replace" method in javascript is not enough. Possibly is it for my project is also a better way, then I would be glad if you also tells me this.

I would need the following:

I have a string with the following content:

var address = 'Beethovenstrasse 1, 97080 Würzburg';

This should be converted to:

var addressNew = '97080/W%C3%9CRZBURG/Beethovenstrasse/1';

And another string

var address = 'Hitzelsbergstr. 84, 83233 Bernau';

This should be converted to:

var addressNew = '83233%20Bernau,%20Hitzelsbergstr.%2084';

To explain why I need this: I need to convert the addresses are in the form of the string "address" in a database. The new string "addressNew" are then part of a link, which starts on mobile devices or TOMTOM navigation NAVIGON and the address to the destination passes by.

Ever Thanks for your help

Why is Wurzburg capital in first while Bernau isn't? Also what's your basic try? — Amit Joki, Jan 23 '15 at 08:57
Yes, you can do this with `replace`. You'd use capture groups. You may or may not need to use a function as the second argument (why does 97080 get `/W` after it, but 83233 gets `%20`?). Give it a go. Read the docs. — T.J. Crowder, Jan 23 '15 at 08:57
The two addressNew seem to be in different format. Is that correct? — A. Rama, Jan 23 '15 at 08:58
What did you try so far? Also, are you certain that addresses will always comply to the pattern given? — mritz_p, Jan 23 '15 at 08:58
Why do you need to convert them in such a way? do you need to parse them somewhere or what? Also, they are different. — briosheje, Jan 23 '15 at 08:59
@Amit Joki: The app "navigon" does not require this information in this way, the app "tomtom". — Thomas, Jan 23 '15 at 09:03
@ T.J. Crowder: The app "navigon" does not require this information in this way, the app "tomtom". The strings are needed different. I have expressed something wrong with the variables. Let's say that the first string is "var addressNewNavigon" and the second "var addressNewTomtom". — Thomas, Jan 23 '15 at 09:06

score 0 · Accepted Answer · edited Jan 23 '15 at 09:01

0

A simple solution:

var address = 'Beethovenstrasse 1, 97080 Würzburg';
var parts = address.split(', ');
var newString = parts[1] + '/' + parts[0];
console.log(encodeURIComponent(newString));

This solution is very specific and does not handle other formats, but you should get some ideas.

edited Jan 23 '15 at 09:01

ntalbs

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answered Jan 23 '15 at 09:00

andeersg

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That's a very good approach, now I have this only bring in the correct order. – Thomas Jan 23 '15 at 09:16
I'm not sure what you mean by "now I have this only bring in the correct order"? – andeersg Jan 23 '15 at 09:17

score -1 · Answer 2 · answered Jan 23 '15 at 08:57

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You can split the string based on spaces and than you can adjeust the order and repalce characters with %20

answered Jan 23 '15 at 08:57

Joris Janssen

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This is not easy, the addresse may also be in this form: var address = 'Dr Hans-Kapfinger-Strasse 1, 94057 Bad Kötzing'; or var address = 'Bahnhofstrasse 1, 80000 Munich'; – Thomas Jan 23 '15 at 09:11
but it will always be in the form (street) (street number) (code)(city) ? – Joris Janssen Jan 23 '15 at 12:48

Javascript replace in a string

2 Answers2