Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location
It is wrong code, because the result is the add-in directory/location.
I would like to open a file on the directory.
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can you please explain in detail – Pranay Rana Jan 20 '15 at 08:49
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Assembly.GetExecutingAssembly() returns your executable location not the solution path. Why did you want to achieve the project solution path ? – Rohit Prakash Jan 20 '15 at 08:49
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Because I need to open a file on directory. – John Smith Jan 20 '15 at 09:01
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As per standards, your file should be located in the known(static/dynamic) location at the storage disk. Lets say, either the same location as of your executable or any system specific eg- AppData, Local or UserData locations. – Rohit Prakash Jan 20 '15 at 09:08
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EnvDTE80.Solution2 solution2;
string solutionFileFullName;
string solutionFolderFullName;
Solution2 = (EnvDTE80.Solution2)_applicationObject.Solution;
solutionFileFullName = solution2.FileName;
solutionFolderFullName = System.IO.Path.GetDirectoryName(solutionFileFullName);
Source:
John Smith
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