Java 8 Unreachable Code

Question

I am fairly new to Java and I ran into this problem once or twice in one of my books. This is a super simple program and I just don't understand why it's not working. I know when you use return, anything after it in the method is meaningless. So does this mean after you perform an for statement or an if statement that is a return?

I am using Java 8 on Windows 8 in the latest version of Eclipse.

This is my simple program:

// Find the sum of 1 through 50 and the average.

class SumAndAverage
{
    public static void main(String args[])
    {
        int sum = 0;
        double average = 0;
        for(int i = 1; 1 <= 50; i++)
        {
            sum += i;
        }

// the following code is "unreachable"
        average = sum / 100;

        System.out.println("The sum is: " + sum);
        System.out.println("The average is " + average);
    }
}

Everyone has been fantastic. After view I realized I had a few typographical errors, and I apologize for that. It was a simple fix, but I really appreciate the help. — killerx615, Jan 17 '15 at 03:01

score 7 · Accepted Answer · answered Jan 17 '15 at 02:19

7

1 is always less than or equal to 50, isn't it? You probably meant to compare i with 50:

for(int i = 1; i <= 50; i++)
{
    sum += i;
}

answered Jan 17 '15 at 02:19

August

12,410
3
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51

Once I replaced 1 with i, that fixed the problem. Thank you so much. – killerx615 Jan 17 '15 at 02:53
Wow, if I had just told him how to fix it, I could have received 6 upvotes. :( – Shahar Jan 19 '15 at 00:42

score 0 · Answer 2 · answered Jan 17 '15 at 02:19

0

for(int i = 1; 1 <= 50; i++)

1 is always less than or equal to 50.

answered Jan 17 '15 at 02:19

Shahar

1,687
2
12
18

Java 8 Unreachable Code

2 Answers2