What does this code mean exactly?

Question

I am just not sure exactly what this section of code means.

try {
    startGame(Integer.parseInt(clickedButton.getLabel()));
} catch (Exception ex) {
    Logger.getLogger(JavaGame.class.getName()).log(Level.SEVERE, null, ex);

What about it is it that you don't understand? – aioobe Jan 16 '15 at 14:04 — aioobe, Jan 16 '15 at 14:04

score 1 · Answer 1 · answered Jan 16 '15 at 14:14

Integer.parseInt() takes in a String and returns an int. So the label of that button must be String that holds a numeric value. The method startGame must take in an int to know which game to start. If the label is NOT a number, it will go into the catch block by throwing a NumberFormatException.

The catch part is log4j that will output to either a log file and/or console (depends on configuation) with the exception.

score 0 · Answer 2 · answered Jan 16 '15 at 14:14

0

If Integer.parseInt() can not convert what ever string that is in clickedButton's Label then it will throw an error.

The error will then get catched by the try catch and create a log message with a level of severe with the stack trace that had happened.

It threw an exception because the clickedButton's Label is not a number.

answered Jan 16 '15 at 14:14

Dave P

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`it will throw an ...` "exception" ;). – Tom Jan 16 '15 at 14:15
@Tom Ya beat me to it :) It will not just send, but log a message, depending on the developers configuration. – Stultuske Jan 16 '15 at 14:17
@Stultuske, I used create rather than send. – Dave P Jan 16 '15 at 14:20

What does this code mean exactly?

2 Answers2