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not very familiar with rubular, would like to know how to use Ruby regex to extract "postreview-should-be-the-cause" from

"{\"source_url\"=>\"http://testing.com/projects/postreview-should-be-the-cause\"}"

the best I am getting is 

check_user = url.split(/\b(\w+)\b/)
=> ["{\"", "source_url", "\"=>\"", "http", "://", "localhost", ":", "3000", "/", "projects", "/", "postreview", "-", "should", "-", "be", "-", "the", "-", "cause", "\"}"]

Still trying various ways. Thanks in advance.

chickensmitten
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3 Answers3

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To extract that substring from the given string, you could use the following to match instead of split.

result = url.match(/\w+(?:-\w+)+/)

Working Demo

hwnd
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You could use string.scan instead of string.split

> "{\"source_url\"=>\"http://testing.com/projects/postreview-should-be-the-cause\"}".scan(/(?<=\/)[^\/"]*(?=[^\/]*$)/)[0]
=> "postreview-should-be-the-cause"
Avinash Raj
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  • Thanks avinash! wow, didnt know about scan. So far, string.scan gave me this output. check_user = url.scan(/\b(\w+)\b/) => [["source_url"], ["http"], ["localhost"], ["3000"], ["projects"], ["postreview"], ["should"], ["be"], ["the"], ["cause"]], how can I merge them back to "postreview-should-be-the-cause"? cause I need to match this later with another model. – chickensmitten Jan 13 '15 at 04:49
  • print the index 0 and get the string you want. – Avinash Raj Jan 13 '15 at 04:56
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\/(?!.*\/)

Split by this.And get the second component.See demo.

https://regex101.com/r/sH8aR8/48

vks
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