Go: execute bash script

Question

How do I execute a bash script from my Go program? Here's my code:

Dir Structure:

/hello/
  public/
    js/
      hello.js
  templates
    hello.html

  hello.go
  hello.sh

hello.go

cmd, err := exec.Command("/bin/sh", "hello.sh")
  if err != nil {
    fmt.Println(err)
}

When I run hello.go and call the relevant route, I get this on my console:

exit status 127 output is

I'm expecting ["a", "b", "c"]

I am aware there is a similar question on SO: Executing a Bash Script from Golang, however, I'm not sure if I'm getting the path correct. Will appreciate help!

score 5 · Accepted Answer · answered Jan 04 '15 at 13:31

exec.Command() returns a struct that can be used for other commands like Run

If you're only looking for the output of the command try this:

package main

import (
    "fmt"
    "log"
    "os/exec"
)

func main() {
    out, err := exec.Command("date").Output()
    if err != nil {
        log.Fatal(err)
    }
    fmt.Printf("The date is %s\n", out)
}

score 2 · Answer 2 · edited May 23 '17 at 11:55

2

You can also use CombinedOutput() instead of Output(). It will dump standard error result of executed command instead of just returning error code. See: How to debug "exit status 1" error when running exec.Command in Golang

edited May 23 '17 at 11:55

Community

1
1

answered Jan 05 '15 at 11:49

Dario Filipović

141
5

score 0 · Answer 3 · answered Jan 04 '15 at 13:01

Check the example at http://golang.org/pkg/os/exec/#Command

You can try by using an output buffer and assigning it to the Stdout of the cmd you create, as follows:

var out bytes.Buffer
cmd.Stdout = &out

You can then run the command using

cmd.Run()

If this executes fine (meaning it returns nil), the output of the command will be in the out buffer, the string version of which can be obtained with

out.String()

Go: execute bash script

3 Answers3