i am writing a program in sbcl to multiply two numbers using add and shift method. while my normal program would run nicely but when i use threads , the program shows no output and no error message. Is there any mistake in code which i should remove.
(use-package :sb-thread)
(defvar *buffer-queue* (make-waitqueue))
(defvar *buffer-lock* (make-mutex :name "buffer-lock"))
(defvar *buffer* (list nil))
(defun writer()
(let ((res 0))
(loop for lpr from 0 to 63
do (let ((end-bit (logand num2 1)))
(with-mutex (*buffer-lock*)
(setf *buffer* (cons end-bit *buffer*))
(setq num2 (ash num2 -1))
(condition-notify *buffer-queue*)
)))))
(defun reader()
(let ((end-bit 0) (res 0))
(with-mutex (*buffer-lock*)
(loop
(condition-wait *buffer-queue* *buffer-lock*)
(loop
(unless *buffer* (return))
(end-bit (car *buffer*))
(setf *buffer* (cdr *buffer*)))))
(if (= end-bit 1)
(setq res (+ res num1)))
(setq num1 (ash num1 1))
(format t "result is ~a.~%" res)
)
)
(let ((num1 (progn
(write-line "Enter first number: ")
(finish-output)
(read)))
(num2 (progn
(write-line "Enter second number: ")
(finish-output)
(read))))
(if (or (= num1 0) (= num2 0))
(write-line "result is 0.0")
(calculator num1 num2))
)
why it is happening?