Linux path to file in Java: correct syntax/convention

Asked Dec 31 '14 at 15:55

Active Dec 31 '14 at 16:12

Viewed 106 times

I am trying to read in an Mp4 file as a starter to learning JavaFX but cannot get the path correct:

public class Main extends Application {

@Override
public void start(Stage primaryStage){
    Player player = new Player("file:/home/dave/Player/src/resources/small.mp4");

and the error is:

Exception in Application start method
Exception in thread "main" java.lang.RuntimeException: Exception in Application start  method
at com.sun.javafx.application.LauncherImpl.launchApplication1(LauncherImpl.java:875)
at com.sun.javafx.application.LauncherImpl.lambda$launchApplication$147(LauncherImpl.java:157)
at com.sun.javafx.application.LauncherImpl$$Lambda$1/142257191.run(Unknown Source)
at java.lang.Thread.run(Thread.java:745)
Caused by: MediaException: UNKNOWN : com.sun.media.jfxmedia.MediaException: Could not create player! : com.sun.media.jfxmedia.MediaException: Could not create player!

I'm using Linux (Ubuntu) with IntelliJ and JDK 8. I'm sure this is simple one.

asked Dec 31 '14 at 15:55

Steerpike

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[this](http://stackoverflow.com/questions/24090356/javafx-mediaplayer-could-not-create-player-error-in-ubuntu-14-04) might help. – SMA Dec 31 '14 at 15:59
1

Your exception isn't filenotfound. It's an unsupported file format and your player can't play it. – Elliott Frisch Dec 31 '14 at 16:02
thanks, back to Windows I go. – Steerpike Dec 31 '14 at 16:13

Linux path to file in Java: correct syntax/convention

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