How to replace a character in a string with a non ascii character in python?

Question

I want to replace the number sign (#) with a character similar to that called music sharp sign (♯). I tried the following line but didnt work.

res['n'].replace('#', '♯')

I also tried these and also didnt work fine.

res['n'].replace('#', u'♯')
res['n'].replace('#', '\xe2')

Anyone got any idea about the situation?

It "didnt work". What was the error? It works perfectly fine to me. What is `res`? — sushain97, Dec 31 '14 at 09:24
Maybe you were expecting `replace()` to modify the string in place? `replace()` doesn't do that; it creates a new string. You would need to write `res['n'] = res['n'].replace('#', '♯')`. — Warren Weckesser, Dec 31 '14 at 09:32
Good point @ceremcem: Also, `'\xe2\x99\xaf'.decode('utf-8') == u'\u266f'`. — PM 2Ring, Dec 31 '14 at 12:06

score 2 · Accepted Answer · answered Dec 31 '14 at 09:35

2

res="He##o"
res=res.replace("#","♯")
print res

o/t He♯♯o

answered Dec 31 '14 at 09:35

Prakash Kuma

score 0 · Answer 2 · answered Dec 31 '14 at 09:27

0

import re
text = ' '
re.sub(' ', '\x00', text)

Why not you use this?

answered Dec 31 '14 at 09:27

nEO

Why do you think this is even vaguely relevant to the question? – PM 2Ring Dec 31 '14 at 12:04

score 0 · Answer 3 · answered Dec 31 '14 at 09:45

0

Replace returns the changed string, strings cannot be changed themselves. Try

res['n'] = res['n'].replace('#', '♯')

answered Dec 31 '14 at 09:45

RemcoGerlich

3 Answers3