Different Output for b=+1 in java

Question

I executed the below program

    int b = 0;
    b=+1;
    System.out.println(b);
    b=+1;
    System.out.println(b);
    b=+1;
    System.out.println(b);

and got output like 1 always. Why is the value of b incrementing in the first increment and why its not incrementing in the second and third incrementing operation?

score 4 · Accepted Answer · answered Dec 29 '14 at 07:14

4

Reverse the = and + symbols. Unary + isn't what you want.

b+=1;

or

b++;

or

++b;

Unary plus is b = (+1); or just b = 1.

answered Dec 29 '14 at 07:14

Elliott Frisch

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score 4 · Answer 2 · answered Dec 29 '14 at 07:14

4

you are doing an assignment here with value +1

int literal allows leading + and - sign

you want

b += 1

answered Dec 29 '14 at 07:14

jmj

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akash · Answer 3 · 2014-12-29T07:22:23.980

2

b=+1 means b = +1 here + is unary operator and you are just giving sign to the digit (which indicates positive value) while you want add and assigment operator b += 1 means b = b +1 to increment the value.

edited Dec 29 '14 at 07:22

answered Dec 29 '14 at 07:15

akash

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Different Output for b=+1 in java

3 Answers3