Fastest way to filter objects in array by their value

Question

Here is my array of objects:

var arr = [
    {name:"Mike", age:17},
    {name:"John", age:21},
    {name:"Sam", age:32},
    {name:"Mark", age:23}
]

For instance I have hundredth of thousands of objects in this array.

What is the fastest way to filter it by age (greatest to least)?

Here is my expected output:

var arr = [
    {name:"Sam", age:32},
    {name:"Mark", age:23}
    {name:"John", age:21},
    {name:"Mike", age:17},      
]

filter `greatest to least` sounds more like sort. What is expected output? — charlietfl, Dec 22 '14 at 11:24
You might want to check out something like Lodash (https://egghead.io/lessons/core-javascript-introduction-to-lodash) — Varedis, Dec 22 '14 at 11:27

Christos · Accepted Answer · 2014-12-22T11:35:27.663

1

I think that you need is sorting. So you could try something like this:

// for sorting them from the greatest to the lower
function compare(a,b) {
   return b.age-a.age;
}

arr.sort(compare);

If you want to sort them from the lower to the greatest, you have to use the following compare

function compare(a,b) {
   return a.age-b.age;
}

Please have a look here JSFiddle.

edited Dec 22 '14 at 11:35

answered Dec 22 '14 at 11:27

Christos

your code sorted from the least to greatest, not greatest to least – Michael Dec 22 '14 at 11:32
Shorter: `return a.age - b.age;` – Felix Kling Dec 22 '14 at 11:33

1 Answers1