//My question was so long So I reduced.
In scheme, user-made procedures consume more time than built-in procedures? (If both's functions are same)
//This is my short version question. //Below is long long version question.
EX 1.23 is problem(below), why the (next) procedure isn't twice faster than (+ 1)?
This is my guess.
reason 1 : (next) contains 'if' (special-form) and it consumes time.
reason 2 : function call consumes time.
http://community.schemewiki.org/?sicp-ex-1.23 says reason 1 is right.
And I want to know reason 2 is also right.
SO I rewrote the (next) procedure. I didn't use 'if' and checked the number divided by 2 just once before use (next)(so (next) procedure only do + 2). And I remeasured the time. It was more fast than before BUT still not 2. SO I rewrote again. I changed (next) to (+ num 2). Finally It became 2 or almost 2. And I thought why. This is why I guess the 'reason 2'. I want to know what is correct answer.
ps. I'm also curious about why some primes are being tested (very?) fast than others? It doesn't make sense because if a number n is prime, process should see from 2 to sqrt(n). But some numbers are tested faster. Do you know why some primes are tested faster?
Exercise 1.23. The smallest-divisor procedure shown at the start of this section does lots of needless testing: After it checks to see if the number is divisible by 2 there is no point in checking to see if it is divisible by any larger even numbers. This suggests that the values used for test-divisor should not be 2, 3, 4, 5, 6, ..., but rather 2, 3, 5, 7, 9, .... To implement this change, define a procedure next that returns 3 if its input is equal to 2 and otherwise returns its input plus 2. Modify the smallest-divisor procedure to use (next test-divisor) instead of (+ test-divisor 1). With timed-prime-test incorporating this modified version of smallest-divisor, run the test for each of the 12 primes found in exercise 1.22. Since this modification halves the number of test steps, you should expect it to run about twice as fast. Is this expectation confirmed? If not, what is the observed ratio of the speeds of the two algorithms, and how do you explain the fact that it is different from 2?
Where the book is : http://mitpress.mit.edu/sicp/full-text/book/book-Z-H-11.html#%_sec_1.2.6