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Looking at the documentation for Parse.Promise.when (https://www.parse.com/docs/js/symbols/Parse.Promise.html#.when), currently, there are two ways of specifying it. The first is with comma separated input parameters for "when" and followed by comma separated inputs for the function in "then" 

Parse.Promise.when(p1, p2, p3).then(function(r1, r2, r3) {
    console.log(r1);  // prints 1
    console.log(r2);  // prints 2
    console.log(r3);  // prints 3
  });

and the Second is with an array input for "when" followed by comma separated inputs for the function in "then." 

  var promises = [p1, p2, p3];
  Parse.Promise.when(promises).then(function(r1, r2, r3) {
    console.log(r1);  // prints 1
    console.log(r2);  // prints 2
    console.log(r3);  // prints 3
  });

My question is: For the function inside "then," is there a easy way to specify an infinite amount of inputs without actually having to put in an infinite amount of inputs? In other words, is there a way to reproduce this in a simple way? 

var promises = [p1, p2, p3];
      Parse.Promise.when(promises).then(function(r1, r2, r3,.............∞) {
        console.log(r1);  // prints 1
        console.log(r2);  // prints 2
        console.log(r3);  // prints 3
        .
        .
        .
        .
        .
        ∞
      });

I tried using the "arguments" variable but it does not work in this case. It seems I have to put in one by one the parameters r1,r2,r3...∞. Does anyone know a way around this? Please help

user3145336
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  • Can you show us the code where you tried using the `arguments` variable? I'm pretty sure that should have worked. – JLRishe Dec 17 '14 at 12:34

1 Answers1

0

No, but there will be.

ECMAScript 6 features rest parameters which allow you to do this:

Parse.Promise.when(promises).then(function(r1, r2, r3, ....rest) {
     console.log(r1); // prints 1
     console.log(rest); // an array with the rest of the parameters.
});

In EcmaScript 5 you need to use arguments:

Parse.Promise.when(promises).then(function() {
     console.log(arguments[0]); // prints 1
     // prints 2 in the first iteration all the way to the last one
     for(var i = 1; i < arguments.length; i++){
         console.log(arguments[i]); 
     });
});
Benjamin Gruenbaum
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