os.system python function in a while loop

Question

I am trying to make a simple python script to automatically click in ubuntu 14.04.

here is my code

#!/usr/bin/python
import os
clickCounter = 0
while clickCounter == 0:
    timeNow = os.system('date +\"%s\"')
    if timeNow > 10:
        os.system('xdotool click 1')
        clickCounter = clickCounter + 1

however, for some reason, all it will do is print out the time again and again until i close the terminal. if anyone can help me it would be very appreciated

[`os.system`](https://docs.python.org/2/library/os.html#os.system) returns the *exit status* of the command, not its standard output. And for the love of `$DEITY`, don't shell out to `date` to get the time! There's the entire [`time`](https://docs.python.org/2/library/time.html#time.time) module! — Jonathon Reinhart, Dec 14 '14 at 00:16
@JonathonReinhart Thank you, i can't believe i forgot about time.time() — Owen Boucher, Dec 14 '14 at 00:23

Reut Sharabani · Accepted Answer · 2014-12-14T00:55:46.673

-1

If you still need to use os.system you should do this:

timeNow = os.popen('date +\"%s\"').read()

A better way is using subprocess:

import subprocess
proc = subprocess.Popen(('date +\"%s\"'.split(), stdout=subprocess.PIPE, shell=True)
(timeNow, err) = proc.communicate()

But as stated in comments - in your case use time

edited Dec 14 '14 at 00:55

answered Dec 14 '14 at 00:43

Reut Sharabani

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score -1 · Answer 2 · answered Dec 14 '14 at 02:13

os.system returns exit status. If you need to get the command's output to a variable try,

import commands

import os

clickCounter = 0

while clickCounter == 0:

timeNow = commands.getoutput('date +\"%s\"')

if timeNow > 10:       

    os.system('xdotool click 1')

    clickCounter = clickCounter + 1

os.system python function in a while loop

2 Answers2

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