sleep in for loop for total iteration time of 2 minutes

Question

I have a for loop inside a while (1) and I want the loop to average approx 2 minutes through each entire for loop cycle. This requires sleeping between each iteration for a different time based on execution time of the iteration and time remaining in my 2 minute shot clock. Any ideas.

I was moving towards something

while(true)
{
   unsigned long begin_loop = OCX::micro_stamp();
   for (int i = 0; i < _vector.size(); i++) 
    {
        unsigned long start = OCX::micro_stamp();
        unsigned long avg = ( ( begin_loop - start) / ( i + 1 ) );
        usleep ( ( 120000000 - ( (_vector.size() - i) * avg ) ) / ( _vector.size() - i ) );
        try
        {



        }
        catch {
        }
   }
}

Create an event object and wait on that towards the end of each loop iteration. — 500 - Internal Server Error, Dec 12 '14 at 22:30
I plan to sleep at the end of each iteration but need to know the math behind how to calculate the sleep time at the end of each iteration as it will vary. — sjohnson, Dec 12 '14 at 22:35
The sleep time is going to be something along the lines of `120 - (now - topOfLoopTime).TotalSeconds`. — 500 - Internal Server Error, Dec 12 '14 at 22:39
that would cause the first iteration to sleep very long and the last to not sleep at all. — sjohnson, Dec 12 '14 at 22:40
I was envisioning `topOfLoopTime` to be taken at the top of the loop body (within the loop). — 500 - Internal Server Error, Dec 12 '14 at 23:07

jmatula · Answer 1 · 2014-12-12T23:15:16.553

0

At the end of each iteration, sleep for ((120 - total elapsed time) / (vector.size() - i))

edited Dec 12 '14 at 23:15

answered Dec 12 '14 at 23:09

jmatula

1
1

score 0 · Accepted Answer · answered Dec 17 '14 at 13:52

0

At the end of each iteration, sleep for

((120000000 - total elapsed microseconds) / (vector.size() - i))

answered Dec 17 '14 at 13:52

jmatula

38
4

sleep in for loop for total iteration time of 2 minutes

2 Answers2